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Taylor Development

sin(x)/x

Take 5 to 10 minutes to try and graph sin(x)x\frac{\sin(x)}{x}.

Then verify you drawing with a graphing tool like Desmos.

Did you get it right ? Or are some parts completely off ? If so, can you imagine why they are the way they are ?

Solution

First sin(x)\sin(x) varies between 1-1 and 11, and therefore sin(x)×1x\sin(x)\times\frac{1}{x} varies between 1x-\frac{1}{x} and 1x\frac{1}{x}. Our graph will look like the graph of sin\sin, but it will be bounded by the graphs of 1x-\frac{1}{x} and 1x\frac{1}{x}.

Then, around 0 : sin(x)sin(x) and xx are very similar (we say that they are equivalent and we write it sin(x)x\sin(x) \sim x)

And since dividing a number by itself gives 11, sin(x)x1\frac{\sin(x)}{x} \approx 1 as we get close to 0.

One objection might be that we are dividing by xx which is almost 00, so the result should tend to infinity ; but actually since sin(x)\sin(x) is also very close to 0, they compensate each other and the result tends to 1 because sin(x)x\sin(x) \approx x.